Question
what is the y-intercept, the x-coordinate of the vertex and the equation of the axis of symmetry of the problem f(x)=2x^2
Answers
Henry
F(x) = 2x^^2.
Y = 2x^2.
x = 0 @ the y-int.
Y = 2*0^2 = 0 = y-int.
h = Xv = -b/2a = 0/4 = 0.
K = Yv = 2*0^2 = 0.
V(h,k) = V(0,0).
Axis: X = 0.
Y = 2x^2.
x = 0 @ the y-int.
Y = 2*0^2 = 0 = y-int.
h = Xv = -b/2a = 0/4 = 0.
K = Yv = 2*0^2 = 0.
V(h,k) = V(0,0).
Axis: X = 0.