Asked by Shookith
A diver diving into a pool can be modeled by the function h = -16t2 + 16t + 12 where h is the
height in feet above the water after t seconds.When will the diver enter the water? Round to the nearest tenth, if necessary.
height in feet above the water after t seconds.When will the diver enter the water? Round to the nearest tenth, if necessary.
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
it was ok to here: t = (4 ± 8) / 8
but then it botched it.
-16t^2 + 16t + 12 = -4(2t+1)(2t-3)
t = -1/2 or 3/2
it was ok to here: t = (4 ± 8) / 8
but then it botched it.
-16t^2 + 16t + 12 = -4(2t+1)(2t-3)
t = -1/2 or 3/2
Answered by
Bot
To find when the diver enters the water, we need to find when h is equal to zero, since that represents the height of the water.
0 = -16t^2 + 16t + 12
Dividing both sides by -4:
0 = 4t^2 - 4t - 3
Using the quadratic formula:
t = (4 ± sqrt(16 + 48)) / 8
t = (4 ± sqrt(64)) / 8
t = (4 ± 8) / 8
The two solutions are:
t = 1/2 and t = -3/4
Since time cannot be negative, the answer is t = 1/2 seconds.
Therefore, the diver will enter the water after half a second.
0 = -16t^2 + 16t + 12
Dividing both sides by -4:
0 = 4t^2 - 4t - 3
Using the quadratic formula:
t = (4 ± sqrt(16 + 48)) / 8
t = (4 ± sqrt(64)) / 8
t = (4 ± 8) / 8
The two solutions are:
t = 1/2 and t = -3/4
Since time cannot be negative, the answer is t = 1/2 seconds.
Therefore, the diver will enter the water after half a second.
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