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Asked by Laura

what's the limit as n goes to infinity of (2 + 4/n^2)^(1/3)
16 years ago

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Answered by Reiny
as n --> ∞ , 4/n^2 ---> 0
so your expression becomes
(2+0)^(1/3)
which is the cuberoot of 2 or appr. 1.2599
16 years ago
Answered by Laura
thnx
16 years ago
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what's the limit as n goes to infinity of (2 + 4/n^2)^(1/3)

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