Asked by James

Limit(7x+6x^2) / (7x^2+6x)
x->inf

Answers

Answered by Reiny
divide top and bottom by x^2 to get

lim (7/x + 6)/(7 + 6/x)
as x ---> inf
both 7/x and 6/x ---> 0
so we are left with
(0 + 6)/(7 + 6) = 6/7
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