Asked by Chopsticks

At standard temperature, a gas has a volume of 275mL. The temperature is then increased to 130. Celcius, and the pressure is held constant. What is the new volume?

How do I work this?

v1 = 275mL
t1 = 130. C or 403K
v2=???
t2 = ???

Can someone help me please?
Answered by DrBob222
The problem lists the gas at standard temperature which is 273 K. So T1 is 273, T2 is 403, V1 = 275 and you solve for V2. Note the correct spelling of celsius.
Answered by Chopsticks
Ahh I gotcha. So standard tempature is always 273k?
Answered by DrBob222
You know STP stands for "standard temperature & pressure." Standard T is 273 and standard P is 1 atm or 760 mm Hg.
Answered by bobpursley
Well...Some in the world has differing standards.
http://en.wikipedia.org/wiki/Standard_conditions_for_temperature_and_pressure
Answered by cocorballs
you guys are a bunch of filthy cheaters
Answered by Bailey
The answer is 406 mL
Answered by haggai
show working out
Answered by Anonymous
V2= V1T2/T1

=(0.28L)(403.15K)/(273.15K)
=0.41L
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