Asked by Em
At a certain temperature, the reaction has Kc = 5 x 108. If a reaction mixture at equilibrium contains 0.26 M of H2 and 0.087 M of Cl2, what is the concentration of HCl?
Answers
Answered by
DrBob222
.....H2 + Cl2 ==> 2HCl
E...0.26..0.087....x
Kc = (HCl)^2/(H2)(Cl2)
You know Kc, (H2), and (Cl2), substitute and solve for HCl.
E...0.26..0.087....x
Kc = (HCl)^2/(H2)(Cl2)
You know Kc, (H2), and (Cl2), substitute and solve for HCl.
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