H2 + Cl2 ==> 2HCl
Kc = (HCl)^2/(H2)(Cl2)
You know Kc, (H2) and (Cl2). The only unknown is (HCl). Substitute and solve for that.
I was wondering if I had to rearrange the equilibrium constant equation to work out the concentration of HCl (product).
Thanks for your help.
Kc = (HCl)^2/(H2)(Cl2)
You know Kc, (H2) and (Cl2). The only unknown is (HCl). Substitute and solve for that.
Kc = [HCl]^2 / ([H2] * [Cl2])
Since you have the values for the concentrations of H2 and Cl2, you can substitute these values into the expression and solve for the concentration of HCl.
Substituting [H2] = 0.48 M and [Cl2] = 0.23 M into the expression, you have:
Kc = [HCl]^2 / (0.48 * 0.23)
Now, rearrange the equation to solve for [HCl]:
[HCl]^2 = Kc * (0.48 * 0.23)
[HCl] = √(Kc * (0.48 * 0.23))
Plugging in the given value for Kc (5 x 10^8), you can calculate the concentration of HCl at equilibrium.