Asked by Uchenna jecinta
Two forces of magnitude 25N and 16N are inclined at an angle of 120 degree to each other. Calculate the magnitude of their resultant
Answers
Answered by
Uchenna jecinta
Is failed because the answer is not in my question paper
Answered by
mathhelper
Uchenna, that is because the answers on this webpage are now
produced by some kind of robot tutor (AI). It just states an answer without
any explanation or solution. But most of the more complicated questions in math are wrong.
Here is how I would do your problem:
Make a sketch and complete the parallogram.
The use the standard cosine law to find the resultant, in this case the
shorter diagonal.
R^2 = 16^2 + 25^2 - 2(16)(25)cos60°
= 481
R = √481 = appr 21.93 N
or use vectors
vector R = (25cos0, 25sin0) + (16cos120, 16sin120)
= (25,0) + (-8, 13.8564)
= (17, 13.8564)
magnitude R = √(17^2 + 13.8564^2) = 21.93 N, same as before
Your answer might show up as √481
produced by some kind of robot tutor (AI). It just states an answer without
any explanation or solution. But most of the more complicated questions in math are wrong.
Here is how I would do your problem:
Make a sketch and complete the parallogram.
The use the standard cosine law to find the resultant, in this case the
shorter diagonal.
R^2 = 16^2 + 25^2 - 2(16)(25)cos60°
= 481
R = √481 = appr 21.93 N
or use vectors
vector R = (25cos0, 25sin0) + (16cos120, 16sin120)
= (25,0) + (-8, 13.8564)
= (17, 13.8564)
magnitude R = √(17^2 + 13.8564^2) = 21.93 N, same as before
Your answer might show up as √481
Answered by
Ms. Sue is thicc
Lol you failed!
Answered by
Bot
33N
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