Asked by okowju Destiny
two forces with magnitude of 25N and 18N respectively are inclined at an angle of 120degree to each other. calculate the resultant force and the angle it makes with the 18N force.
Answers
Answered by
Henry
Fr = 25[120o] + 18[0o].
Fr = (25*Cos120+18) + (25*sin120)i.
Fr = 5.5 + 21.65i = 22.3N[75.7o] = The resultant force.
Fr is 75.7o N. of the 18N. force.
Fr = (25*Cos120+18) + (25*sin120)i.
Fr = 5.5 + 21.65i = 22.3N[75.7o] = The resultant force.
Fr is 75.7o N. of the 18N. force.
Answered by
Blessing Ayuba
Fr=25[120°]+18[0°]
Fr=[25*cos 120+18+[25*sin120]
Fr=5•5+21•65 =22•3N[75•7]= the resultant force
Fr is 75•70N. of the 18 N. force
Fr=[25*cos 120+18+[25*sin120]
Fr=5•5+21•65 =22•3N[75•7]= the resultant force
Fr is 75•70N. of the 18 N. force
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