Asked by raja
Three forces of magnitude 6N,6N,√72N act at a corner of a cube along three sides .resultant of the force is a)12N along on b)18N along oa c)18N along of d)12N along oe
Answers
Answered by
Steve
the magnitude z is
z^2 = 6^2+6^2+72 = 144
z = 12
Not sure where N and E are ...
z^2 = 6^2+6^2+72 = 144
z = 12
Not sure where N and E are ...
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