Asked by FAHAT
Volume of acid is 20.30cm3 of hydrochloride was tertired against 25cm3 of 0.1 NaOH solution. Calculate the concentration of the acid in (mole per dm3).And (gram per dm3)
Answers
Answered by
DrBob222
HCl + NaOH ==> NaCl + H2O
moles NaOH = M x L = 0.1 M x 0.025 L = 0.0025
From the equation you see that 1 mol NaOH = 1 mol HCl; therefore, mols NaOH = 0.0025
Then M NaOH = mols/L = 0.0025/0.0203 L =0.123
moles NaOH = M x L = 0.1 M x 0.025 L = 0.0025
From the equation you see that 1 mol NaOH = 1 mol HCl; therefore, mols NaOH = 0.0025
Then M NaOH = mols/L = 0.0025/0.0203 L =0.123
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