Asked by anonymous
what volume of butyric acid would be needed to make 25.0mL of a 1.0M solution?
oh i forgot to mention that butyric acid is a liquid with a density of 1.75gr/mL
can you please explain the steps more?
thanks
oh i forgot to mention that butyric acid is a liquid with a density of 1.75gr/mL
can you please explain the steps more?
thanks
Answers
Answered by
DrBob222
There isn't much explaining.
Definition of molarity is
M = # moles/L solution.
So you want moles. You have L soln in the problem as 25.0 mL = 0.025L. And you have M in the problem as 1.0 M. So all we need to do is find moles needed.
M = moles/L or moles = M x L = 1.0 x 0.025 = 0.025 moles.
Now, how do we find moles?
moles = grams/molar mass
0.025 moles = grams/molar mass.
What's the molar mass. Approximately 88 so 0.025 = g/88 and g = 0.025*88 = 2.20 g approximately.
The problem asks for volume. Use the density to convert grams to mL.
Definition of molarity is
M = # moles/L solution.
So you want moles. You have L soln in the problem as 25.0 mL = 0.025L. And you have M in the problem as 1.0 M. So all we need to do is find moles needed.
M = moles/L or moles = M x L = 1.0 x 0.025 = 0.025 moles.
Now, how do we find moles?
moles = grams/molar mass
0.025 moles = grams/molar mass.
What's the molar mass. Approximately 88 so 0.025 = g/88 and g = 0.025*88 = 2.20 g approximately.
The problem asks for volume. Use the density to convert grams to mL.
Answered by
anonymous
thank you
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