Asked by kathy
what volume of 16 sulfuric acid must be used to prepare 1.5 L of a 0.10 M H2SO4 solution
Answers
Answered by
DrBob222
16 what? 16M?
c1v1 = c2v2
c = concn
v = volume
16M*v1 = 0.1*1.5M
Solve for v1.
c1v1 = c2v2
c = concn
v = volume
16M*v1 = 0.1*1.5M
Solve for v1.
Answered by
Graham
Assuming that's 16M, find volume V when:
(16M) * V = (0.10M) * (1.5L)
(16M) * V = (0.10M) * (1.5L)
Answered by
Clos
9.4 mL of acid
Answered by
Anonymous
Where is the work tho?
Answered by
.....
16 M*V=1.5 L * 0.10 M
V=(1.5 L * 0.10 M)/16M
=.00937L (9.375ml)
V=(1.5 L * 0.10 M)/16M
=.00937L (9.375ml)
Answered by
Isaya Obedi
From dilution law
C1V1=C1V2
16M×V1=1.5M×0.10M
V1=0.00937L or 9.375mL
C1V1=C1V2
16M×V1=1.5M×0.10M
V1=0.00937L or 9.375mL
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