Asked by Anonymous
                Kevin collected 7 times as many rocks as David. When Kevin gave David some of his rocks, they each had 32. How many rocks had Kevin given to David?
            
            
        Answers
                    Answered by
            mathhelper
            
    David's rocks --- x
Kevin's rocks --- 7x
number of rocks in the exchange --- k
x + k = 32
7x - k = 32
add them
8x = 64
x = 8
so in x + k = 32, 8+k = 32
k = 24
state your conclusion.
    
Kevin's rocks --- 7x
number of rocks in the exchange --- k
x + k = 32
7x - k = 32
add them
8x = 64
x = 8
so in x + k = 32, 8+k = 32
k = 24
state your conclusion.
                    Answered by
            Bosnian
            
    K = Kevin's rocks
D = David's rocks
Kevin collected 7 times as many rocks as David means:
K = 7 D
x = number of of rocks that Kevin gave to David
When Kevin gave x rock to David
Kevin have K - x = 7 D - x rocks.
David have D + x rocks.
Each had 32 rocks means.
7 D - x = 32
D + x = 32
The solution of this system of equations is:
D = 8 , x = 24
Kevin given to David 24 rocks.
Check result.
If David have 8 rocks, Kevin have:
7 • 8 = 56 rocks
When Kevin gave 24 rock to David , Kevin have 56 - 24 = 32 rocks.
When Kevin gave 24 rock to David,
David have 24 + 8 = 32 rocks
    
D = David's rocks
Kevin collected 7 times as many rocks as David means:
K = 7 D
x = number of of rocks that Kevin gave to David
When Kevin gave x rock to David
Kevin have K - x = 7 D - x rocks.
David have D + x rocks.
Each had 32 rocks means.
7 D - x = 32
D + x = 32
The solution of this system of equations is:
D = 8 , x = 24
Kevin given to David 24 rocks.
Check result.
If David have 8 rocks, Kevin have:
7 • 8 = 56 rocks
When Kevin gave 24 rock to David , Kevin have 56 - 24 = 32 rocks.
When Kevin gave 24 rock to David,
David have 24 + 8 = 32 rocks
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