Question

A steady current 0.80A was passed through an aqueous solution of tetraoxosulphate vi acid for 7 hours. Calculate the volume of hydrogen gas that was liberated at STP
I can calculate it I need help please
A note: Tetraoxosulphate vi acid is NOT an acceptable name for H2SO4 by IUPAC standards. An acceptable name is sulfuric acid (or sulphuric acid if in the UK).
How many coulombs?
Coulombs = C = amperes x seconds
C = 0.80 A x 7 hrs x (60 min/hr) x (60 sec/min) = 20,160
96,485 C will liberate 11.2 L H2 gas @ STP so you will get
11.2 L H2 gas x (20,160/96,485) = ? L

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