Asked by Tope
Current if45 amphere is pass through a solution of gold salt for one hour 45 minute calculate ( 1) the mass of gold deposited
Answers
Answered by
DrBob222
You don't say what gold salt but I'll assume it is Au^3+.
coulombs = amperes x seconds
C = 45 x 1.5 hours x (60 min/hr) x (60 sec/min) = 5400 C
96,485 coulombs will deposit 197/3 or 65.7 g Au so
65.7 g x (5400/96,485) = ?g Au.
coulombs = amperes x seconds
C = 45 x 1.5 hours x (60 min/hr) x (60 sec/min) = 5400 C
96,485 coulombs will deposit 197/3 or 65.7 g Au so
65.7 g x (5400/96,485) = ?g Au.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.