Question

Current if45 amphere is pass through a solution of gold salt for one hour 45 minute calculate ( 1) the mass of gold deposited

Answer 1

You don't say what gold salt but I'll assume it is Au^3+.
coulombs = amperes x seconds
C = 45 x 1.5 hours x (60 min/hr) x (60 sec/min) = 5400 C
96,485 coulombs will deposit 197/3 or 65.7 g Au so
65.7 g x (5400/96,485) = ?g Au.