Asked by Abimbola

A current of 45A is pass through a solution of gold salt for 1hours 45minute. Calculate Mass of gold deposited, b) number of mole deposited c) if the same current is used find the time taken for 5.5g to be deposited
Answered by DrBob222
coulombs = amperes x seconds
coulombs = 45 x 1.75 hr x (60 min/hr) x (60 sec/min) = 283,500
96,485 coulombs will deposit 1/3 of a mol of Au from Au^3+ solutions.
So 1/3 mole x (283,500/96,485) = ? mols Au deposited.
You have all of the info needed. Can you do the last part?
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