Asked by henry
distance between y=1/4x-3 and (-2,1)
Answers
Answered by
oobleck
recall that the distance between Ax+By+C=0 and (h,k) is
|Ah+Bk+C|/√(A^2+B^2)
our line can be written as
x-4y-12 = 0
so plug in your numbers
|Ah+Bk+C|/√(A^2+B^2)
our line can be written as
x-4y-12 = 0
so plug in your numbers
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