Asked by Joyce
At a distance of 2.0 m. from a +8.0 x 10^-6 C charge, the magnitude and direction of the electric field will be?
Answers
Answered by
Damon
Coulomb's law:
F = k q1 q2/r^2
E = force on unit charge
E = F/1 = k q /r^2
= 9*10^9 * 8*10^-6 /4
1.8 *10^4 Newtons/Coulomb
like charges repel so in direction away from positive charge
F = k q1 q2/r^2
E = force on unit charge
E = F/1 = k q /r^2
= 9*10^9 * 8*10^-6 /4
1.8 *10^4 Newtons/Coulomb
like charges repel so in direction away from positive charge
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