Asked by Stacy
what is the distance that a satellite must be from Earths surface if it's period of rotation is 1 day?
I really not sure where to even start..
I really not sure where to even start..
Answers
Answered by
bobpursley
Easy.
Keplers law: r^3=k*T^2
look up for the moon, the radius of its orbit, and period. I get 238,900 miles, and 27 days.
Now you know the period you want, 1 day, so a ratio is
(r/238900)^3= (1/27)^2
solve for r. I get
r=238900(1/27)^2/3 or
r=238900/9= 26500 miles
Look up the numbers, you can get it bit more accurate.
Keplers law: r^3=k*T^2
look up for the moon, the radius of its orbit, and period. I get 238,900 miles, and 27 days.
Now you know the period you want, 1 day, so a ratio is
(r/238900)^3= (1/27)^2
solve for r. I get
r=238900(1/27)^2/3 or
r=238900/9= 26500 miles
Look up the numbers, you can get it bit more accurate.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.