The sum of interior angles of a regular polygon is 1080°
a) Find the size of each exterior angle
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We have a formula for the sum of the angles:
sum of angles = 180(n-2), where n is the number of sides
180(n-2) = 1080
solve for n , now you have the number of angles,
(hint: it is a very common polygon)
divide 1080 by that n to get the size of each angle.
sum of angles = 180(n-2), where n is the number of sides
180(n-2) = 1080
solve for n , now you have the number of angles,
(hint: it is a very common polygon)
divide 1080 by that n to get the size of each angle.
In this case n = 8
All the Exterior Angles of a polygon add up to 360°
Each exterior angle = 360° / n
Each exterior angle = 360° / 8 = 45°
All the Exterior Angles of a polygon add up to 360°
Each exterior angle = 360° / n
Each exterior angle = 360° / 8 = 45°
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