Asked by andrew
determine 3 consecutive even integers if the square of the largest integer is 84 less than the sum of the squares of the two smaller integers
Answers
Answered by
mathhelper
let the middle number be x, the previous even be x-2, and the third
consecutive number be x+2
(x^2 + (x-2)^2) - (x+2)^2 = 84
x^2 + x^2 - 4x + 4 - x^2 - 4x - 4 = 84
x^2 - 8x - 84 = 0
(x-14)(x+6) = 0
x = 14 or x = -6
if x = 14, the 3 integers were : 12, 14, and 16
if x = -6, the 3 integers were : -8, -6, -4
consecutive number be x+2
(x^2 + (x-2)^2) - (x+2)^2 = 84
x^2 + x^2 - 4x + 4 - x^2 - 4x - 4 = 84
x^2 - 8x - 84 = 0
(x-14)(x+6) = 0
x = 14 or x = -6
if x = 14, the 3 integers were : 12, 14, and 16
if x = -6, the 3 integers were : -8, -6, -4
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