Copy your question in google.
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When you see list of results click on :
w w w . a l g e b r a . c o m / c g i - b i n / j u m p - t o - q u e s t i o n . m p l
You will see solution.
Let's say that the first odd integer is represented by n. Since we are looking for consecutive odd integers, the second odd integer would be n + 2, and the third odd integer would be n + 4.
According to the given condition, three times the middle integer (3 * (n + 2)) is equal to the sum of the first and third integers (n + n + 4) plus seven more.
Now we can set up the equation and solve for n:
3 * (n + 2) = (n + n + 4) + 7
Simplifying the equation:
3n + 6 = 2n + 11
Move all the terms with n to one side:
3n - 2n = 11 - 6
n = 5
So the first odd integer (n) is 5.
The second odd integer is n + 2 = 5 + 2 = 7.
The third odd integer is n + 4 = 5 + 4 = 9.
Therefore, the three consecutive odd integers that satisfy the given condition are 5, 7, and 9.