Asked by Tony
Solve the following algebraically using one variable: Find three consecutive even integers such
that the product of the smallest integer and the middle integer is eight less than eleven times the larger integer.
that the product of the smallest integer and the middle integer is eight less than eleven times the larger integer.
Answers
Answered by
Steve
even integers differ by 2, so the three numbers are x, x+2 and x+4. Now you are told that
x(x+2) = 11(x+4)-8
Now solve for x.
x(x+2) = 11(x+4)-8
Now solve for x.
Answered by
bobpursley
let n be the smallest integer
n+2 the middle
n+4 the larger
n*(n+2)+8=11(n+4)
solve for n. I appears to be a quadratic equation
n^2-9n-36=0
(n-12)(n+3)=0
n=12, or n=-3
reject the n=-3 as it is not an even integer.
n+2 the middle
n+4 the larger
n*(n+2)+8=11(n+4)
solve for n. I appears to be a quadratic equation
n^2-9n-36=0
(n-12)(n+3)=0
n=12, or n=-3
reject the n=-3 as it is not an even integer.
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