Asked by Tony

Solve the following algebraically using one variable: Find three consecutive even integers such
that the product of the smallest integer and the middle integer is eight less than eleven times the larger integer.

Answers

Answered by Steve
even integers differ by 2, so the three numbers are x, x+2 and x+4. Now you are told that

x(x+2) = 11(x+4)-8

Now solve for x.
Answered by bobpursley
let n be the smallest integer
n+2 the middle
n+4 the larger

n*(n+2)+8=11(n+4)

solve for n. I appears to be a quadratic equation
n^2-9n-36=0
(n-12)(n+3)=0
n=12, or n=-3
reject the n=-3 as it is not an even integer.
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