Asked by Nelson
determine three consecutive even integers, if the square of the largest integer less the square of the middle integer is 20 less than the square of the smallest integer
Answers
Answered by
oobleck
so, if the numbers are x-2, x and x+2, we have
(x+2)^2 - x^2 = (x-2)^2 - 20
solve for x and you get -2,10
check:
12^2 - 10^2 = 8^2 - 20 -- yep
0^2 - 2^2 = (-4)^2 - 20 -- yep
(x+2)^2 - x^2 = (x-2)^2 - 20
solve for x and you get -2,10
check:
12^2 - 10^2 = 8^2 - 20 -- yep
0^2 - 2^2 = (-4)^2 - 20 -- yep
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