Asked by Anonymous
Determine the period y=-3cos(4x+3pi/2)+1
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Answered by
mathhelper
y=-3cos(4x+3pi/2)+1
= -3 cos [4(x + 3/8 π) + 1
in y = a cos kx, the
period of the cosine curve is 2π/k
in yours:
2π/4 = period
the period is π/2
check: graph the function y=-3cos(4x+3pi/2)+1
h ttps://www.desmos.com/calculator
(you will have to change it to π, Desmos does not understand "pi"
Of course you must delete the space at the front of the URL)
= -3 cos [4(x + 3/8 π) + 1
in y = a cos kx, the
period of the cosine curve is 2π/k
in yours:
2π/4 = period
the period is π/2
check: graph the function y=-3cos(4x+3pi/2)+1
h ttps://www.desmos.com/calculator
(you will have to change it to π, Desmos does not understand "pi"
Of course you must delete the space at the front of the URL)
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