Asked by don
Determine the period length of
y= 2/3 sin (3x/2 )
I had 3pi/2 but the correct answer is 4pi/3 how do you get that???
y= 2/3 sin (3x/2 )
I had 3pi/2 but the correct answer is 4pi/3 how do you get that???
Answers
Answered by
Reiny
period of sin kx is 2π/3, (see your other post)
so for your function,
period = 2π/(3/2)
= 2π(2/3) = 4π/3
so for your function,
period = 2π/(3/2)
= 2π(2/3) = 4π/3
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