(c) n=6,p=0.2
Pr(X=5)=
interpretation:
P(X=5) = C(6,5) (.2)^5 (.8)^1
= 6(.00032)(.8)
= .001536
In each part, assume the random variable X has a binomial distribution with the given parameters. Compute the probability of the event.
(a) n=3,p=0.7
Pr(X=3)=
(b) n=6,p=0.6
Pr(X=6)=
(c) n=6,p=0.2
Pr(X=5)=
(d) n=5,p=0.8
Pr(X=0)=
1 answer