Question

Assume that a random sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.

95% confidence the sample size is 2096 of which 25%are successes

The margin of E= (round to four decimal places as needed)

Answer 1

Margin of error = (1.96)[√(pq/n)]

Note: 1.96 represents 95% confidence.

For p in your problem: .25
For q: 1 - p = q
n = 2096

I let you take it from here to calculate.