Asked by Rob
Assume that a random sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.
95% confidence the sample size is 2096 of which 25%are successes
The margin of E= (round to four decimal places as needed)
95% confidence the sample size is 2096 of which 25%are successes
The margin of E= (round to four decimal places as needed)
Answers
Answered by
MathGuru
Margin of error = (1.96)[√(pq/n)]
Note: 1.96 represents 95% confidence.
For p in your problem: .25
For q: 1 - p = q
n = 2096
I let you take it from here to calculate.