Asked by Jonathan
what if the hypotenuse is 20 and one of the legs are 12 what is the length of the other leg?
Answers
Answered by
mathhelper
x^2 + 12^2 = 20^2
x^2 = 400-144 = 256
x = √256 = 16
or
you might recognize that 20-16-12 is just a multiple of
the popular 5-4-3 right-angled triangle.
x^2 = 400-144 = 256
x = √256 = 16
or
you might recognize that 20-16-12 is just a multiple of
the popular 5-4-3 right-angled triangle.
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