Asked by sherianna
The hypotenuse is x+5 and the legs are 16, and 7 so how would you use the pythagorean theorem.
Answers
Answered by
Steve
use it as you always do:
16^2 + 7^2 = (x+5)^2
and solve for x
x^2+10x+25 = 256+49 = 305
x^2+10x-280 = 0
or, just start with the numbers:
16^2+7^2 = 305
so, x+5 = √305
and work from there.
16^2 + 7^2 = (x+5)^2
and solve for x
x^2+10x+25 = 256+49 = 305
x^2+10x-280 = 0
or, just start with the numbers:
16^2+7^2 = 305
so, x+5 = √305
and work from there.
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