Asked by Bob
4.82 mL of a 0.262 M NaOH solution reacts completly with 4.79 mL of HCl solution according to the balanced chemical reaction shown below:
HCl (aq) + NaOH (aq) -> NaCl*aq) + H2O (I)
What is the molarity of the HCl solution?
4.82 x (1L/1000 mL) = .00482L
4.79 x (1L/1000 mL) = .00479L
(.00482L)(0.262M) = .00126284
(.00126284M/.00479L) = .263 M HCl
I was wondering if I set up and solved this problem correctly?
HCl (aq) + NaOH (aq) -> NaCl*aq) + H2O (I)
What is the molarity of the HCl solution?
4.82 x (1L/1000 mL) = .00482L
4.79 x (1L/1000 mL) = .00479L
(.00482L)(0.262M) = .00126284
(.00126284M/.00479L) = .263 M HCl
I was wondering if I set up and solved this problem correctly?
Answers
Answered by
DrBob222
The set up looks ok. I don't think you rounded properly. I get 0.26364 M which I would round to 0.264 M.
Answered by
DrBob222
By the way, just as a shortcut, when everything is listed in mL, you need not change everything to L.
Ml x M = mL x M.
L x M = moles
mL x M = millimoles.
Ml x M = mL x M.
L x M = moles
mL x M = millimoles.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.