Asked by Jazmin

How much of a 0.23 M NaOH solution is needed to neutralize 27 mL of a 0.85 M sulfuric acid solution? The units are mL.

Can you please explain why you did what did

Thank you
Answered by bobpursley
well, it takes two moles of NaOH to neutralize on mole of sulfuric acid, so

2*.23(Volumebase)=27ml*.85
solve for volumebase
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