Asked by Linda
If 20mL of a 0.100 M NaOH solution are required to titrate 0.25 grams of an unknown acid, what is the equivalent mass of the acid? If the acid actually contains 3 moles of H+ per mole of acid what is the molecular mass of the acid?
Answers
Answered by
DrBob222
mL x N x mew = grams.
20 x 0.1 x mew = 0.25
Solve for milliequivalent weight.
Then equivalent weight = 1000 x mew.
(molar mass/3) = equivalent weight. Solve for molar mass
20 x 0.1 x mew = 0.25
Solve for milliequivalent weight.
Then equivalent weight = 1000 x mew.
(molar mass/3) = equivalent weight. Solve for molar mass
Answer
ялРВ
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.