Asked by Jazmin
How much of a 0.23 M NaOH solution is needed to neutralize 27 mL of a 0.85 M sulfuric acid solution? The units are mL
Answers
Answered by
DrBob222
Write the equation.
2NaOH + H2SO4 ==> H2O + Na2SO4.
moles H2SO4 = M x L = ??
moles NaOH needed = twice that (from the equation).
Then M NaOH = moles NaOH/L NaOH.
Solve for L NaOH.
2NaOH + H2SO4 ==> H2O + Na2SO4.
moles H2SO4 = M x L = ??
moles NaOH needed = twice that (from the equation).
Then M NaOH = moles NaOH/L NaOH.
Solve for L NaOH.
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