Question
Express as a single logarithm
blog_c(x) - dlog_c(y) + log_c(z)
blog_c(x) - dlog_c(y) + log_c(z)
Answers
mathhelper
interpretation:
b log<sub>c</sub> x - dlog<sub>c</sub> y + log<sub>c</sub>c z
= log<sub>c</sub> (x^b) - log<sub>c</sub> (y^d) + log<sub>c</sub> z
= log<sub>c</sub> (x^b z/y^d)
b log<sub>c</sub> x - dlog<sub>c</sub> y + log<sub>c</sub>c z
= log<sub>c</sub> (x^b) - log<sub>c</sub> (y^d) + log<sub>c</sub> z
= log<sub>c</sub> (x^b z/y^d)