x =log5 (sqrt 175) - log5 (sqrt 7)
x = log 5 (sqrt 175/7)
x= log 5(25)
5^x = 25
x = 2
Express as a single logarithm.
log(subsript)5�ã175-log(subscript)5�ã7
2 answers
I did those last couple of steps in my head, here is the way to do it methodically:
x= log5(25)
x = log5 (5^2)
x = 2 log5(5) but log5(5) = 1
x = 2
x= log5(25)
x = log5 (5^2)
x = 2 log5(5) but log5(5) = 1
x = 2