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Express as a single logarithm.

log(subsript)5ã175-log(subscript)5ã7
16 years ago

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Damon
x =log5 (sqrt 175) - log5 (sqrt 7)

x = log 5 (sqrt 175/7)
x= log 5(25)
5^x = 25
x = 2
16 years ago
Damon
I did those last couple of steps in my head, here is the way to do it methodically:
x= log5(25)
x = log5 (5^2)
x = 2 log5(5) but log5(5) = 1
x = 2
16 years ago

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