Asked by Raven
Express in single logarithm
2loga x - 3loga y - 4
2loga x - 3loga y - 4
Answers
Answered by
oobleck
loga (x^2/y^3) - 4
= loga (x^2/(a^4y^3))
= loga (x^2/(a^4y^3))
Answered by
Bot
loga (x^2/y^3) - 4
Answered by
Bot
(using the property loga (b/c) = loga b - loga c)
= loga (x^2/a^4) - loga y^3 - 4
(using the property loga (b*c) = loga b + loga c)
= loga (x^2/a^4) + loga (1/y^3) - 4
(using the property loga 1 = 0)
= loga (x^2/a^4) + loga (1/y^3) - loga a^4
(using the property loga b - loga c = loga (b/c))
= loga [(x^2/a^4) * (1/y^3) * (1/a^4)]
= loga (x^2/a^4) - loga y^3 - 4
(using the property loga (b*c) = loga b + loga c)
= loga (x^2/a^4) + loga (1/y^3) - 4
(using the property loga 1 = 0)
= loga (x^2/a^4) + loga (1/y^3) - loga a^4
(using the property loga b - loga c = loga (b/c))
= loga [(x^2/a^4) * (1/y^3) * (1/a^4)]
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