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A 6 kg mass is resting on a horizontal surface it is determined that a force of 20 N will start the object skidding and keep it...Asked by mary
A 6kg mass is resting on a horizontal surface. it is determined that a force of 20N will start the object sliding and keep it sliding with an acceleration of 0.83. what are the coefficient of static friction and kinetic friction between the mass and the surface?
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Answered by
mary
I need the answer now
Answered by
Anonymous
First the static friction
F = mu m g
20 = mu * 6 * 9.81 (on earth)
mu = 20 / (6*9.81) = 0.34 static
then sliding
F - mu m g = m a
20 - mu (6*9.81) = 6 *0.83
58.9 mu = 20 - 4.98 = 15
mu = 0.25 kinetic
F = mu m g
20 = mu * 6 * 9.81 (on earth)
mu = 20 / (6*9.81) = 0.34 static
then sliding
F - mu m g = m a
20 - mu (6*9.81) = 6 *0.83
58.9 mu = 20 - 4.98 = 15
mu = 0.25 kinetic
Answered by
Anonymous
Sorry to be so slow about the reply. I retired long before you were born I suspect (was a student at Punahoe school when Pearl Harbor was bombed) and have trouble keeping up.
Answered by
Khadija
Really appreciate to the answer thank u guys help a lot
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