Asked by riham

a mass of 9.6 kg is moving horizontally as a force of 2.3 N , directed at 21° below the horizontal , is exerted on it , when the speed is 7.9 m/s, what is the rate at which the force is doing work
Answered by Henry
Rate of doing work = power.
P = Fe*Cos21 * V
P = 2.3*Cos21 * 7.9 = 17 J/s = 17 Watts.
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