m=0.0045kg
E=3.6 J for .13m compression
T=?
Vm @ .05m from equilibrium= ?
P.E.= .5KA^2
therefore find K=F/x
(.0045x9.8)/(.13)
K =.34N/m
T=2pixsprt(m/K)
T= 2xpi x sprt (.0045/.34)
T= .72 secs
B) E=PE+KE
3.6= .5 (3.4)(0)^2 + .2 (.0045)(v^2)
v^2=1600
v=40
A 4.50 g mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end of the spring is fixed to a wall. It takes 3.6J of work to compress the spring by 13.0 cm. If the spring is compressed, and the mass is released from rest. find a) the period of vibration, and b) the velocity of the mass when its is 5.00 cm from the equilibrium.
1 answer
1 answer