Asked by Peaches
A 4.50 g mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end of the spring is fixed to a wall. It takes 3.6J of work to compress the spring by 13.0 cm. If the spring is compressed, and the mass is released from rest. find a) the period of vibration, and b) the velocity of the mass when its is 5.00 cm from the equilibrium.
Answers
Answered by
Anonymous
m=0.0045kg
E=3.6 J for .13m compression
T=?
Vm @ .05m from equilibrium= ?
P.E.= .5KA^2
therefore find K=F/x
(.0045x9.8)/(.13)
K =.34N/m
T=2pixsprt(m/K)
T= 2xpi x sprt (.0045/.34)
T= .72 secs
B) E=PE+KE
3.6= .5 (3.4)(0)^2 + .2 (.0045)(v^2)
v^2=1600
v=40
E=3.6 J for .13m compression
T=?
Vm @ .05m from equilibrium= ?
P.E.= .5KA^2
therefore find K=F/x
(.0045x9.8)/(.13)
K =.34N/m
T=2pixsprt(m/K)
T= 2xpi x sprt (.0045/.34)
T= .72 secs
B) E=PE+KE
3.6= .5 (3.4)(0)^2 + .2 (.0045)(v^2)
v^2=1600
v=40
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.