Question
A 2 kg mass resting on a smooth plane inclined 20 degrees to the horizontal. A cord which is parallel to the plane passes over a massless, frictionless pulley to a 4 kg mass which will drop vertically when released. What will be the speed of the 4 kg mass 4 seconds after it is released from rest?
Answers
on the plane, force down the plane mg*sinTheta. Force up the plane=4g
net force= 4g-2gSintheta=(6g)a
solve for a.
then, speed=at
net force= 4g-2gSintheta=(6g)a
solve for a.
then, speed=at
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