Asked by Anonymous
Mass mA rests on a smooth horizontal surface, mB hangs vertically.If m_{\rm{A}}=13.0 kg and m_{\rm{B}}=3.0 kg in the figure , determine the magnitude of the acceleration of each block.
Answers
Answered by
MathMate
Sorry, Anonymous, we do not have latex installed, at least yet.
I presume the figure looks like this, but a mirror image of it:
o-----T-----mA
|
|
T
|
|
mB
The letter o stands for a pulley.
The answer to the question lies in the formula F=ma
Force exerted on the system is gravity on mB, thus
F=mB*g
Total mass = mA+mB
Acceleration = F/(mA+mB)
If they are connected by a mass-less and frictionless pulley, then the acceleration of each block is identical.
The tension on the string, T, is again found by the formula:
T=mA*a
I presume the figure looks like this, but a mirror image of it:
o-----T-----mA
|
|
T
|
|
mB
The letter o stands for a pulley.
The answer to the question lies in the formula F=ma
Force exerted on the system is gravity on mB, thus
F=mB*g
Total mass = mA+mB
Acceleration = F/(mA+mB)
If they are connected by a mass-less and frictionless pulley, then the acceleration of each block is identical.
The tension on the string, T, is again found by the formula:
T=mA*a
Answered by
thanks
you smell like celery and gulumpkies
Answered by
reem
The figure shows a block (mass massA ) on a smooth horizontal surface, connected by a thin cord that passes over a pulley to a second block (mass
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