Asked by tired and sad failing math girl
Find the values of x and y.
βπΏππ β βπππ , πβ πΏ = 40Β°, πβ π = 90Β°, πβ π = (17π₯ β π¦)Β°, πβ π = (2π₯ + 4π¦)Β°
βπΏππ β βπππ , πβ πΏ = 40Β°, πβ π = 90Β°, πβ π = (17π₯ β π¦)Β°, πβ π = (2π₯ + 4π¦)Β°
Answers
Answered by
mathhelper
Assuming that you have named the similar triangles so that corresponding
angles are equal, that is
πβ πΏ = πβ π , etc
we have to match up πβ N with πβ π
we know 2 of the angles of βπΏππ, so πβ N = 180 - 40 - 90 = 50Β°
so πβ πΏ = πβ π
17x - y = 40 ----> y = 17x - 40
πβ N with πβ π
2x + 4y = 50
substitution:
2x + 4(17x-40) = 50
2x + 68 - 4x = 50
-2x = -18
x = 9
then y = 17(9) - 40 = 113Β°
check my arithmetic
angles are equal, that is
πβ πΏ = πβ π , etc
we have to match up πβ N with πβ π
we know 2 of the angles of βπΏππ, so πβ N = 180 - 40 - 90 = 50Β°
so πβ πΏ = πβ π
17x - y = 40 ----> y = 17x - 40
πβ N with πβ π
2x + 4y = 50
substitution:
2x + 4(17x-40) = 50
2x + 68 - 4x = 50
-2x = -18
x = 9
then y = 17(9) - 40 = 113Β°
check my arithmetic
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