Question

Find possible values of the constant p if the expression px²+12x+4p+px is a perfect square

Answers

Answered by oobleck
px^2+12x+4p+px = px^2 + (p+12)x + 4p = p(x^2 + (1 + 12/p)x + 4)
We need p to be a perfect square, and it is clear by inspection that if p=4, we have
4(x^2 + 4x + 4) = (2(x+2))^2
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions