Asked by Valerie
Find all values of x such that \sqrt{4x^2} + \sqrt{x^2} = 6 + 3x.
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
√(4x^2) + √x^2 = 3x+6
2|x| + |x| = 3x+6
3|x| = 3x+6
If x >= 0,
3x = 3x+6
no solutions
If x < 0,
-3x = 3x+6
x = -1
√(4x^2) + √x^2 = 3x+6
2|x| + |x| = 3x+6
3|x| = 3x+6
If x >= 0,
3x = 3x+6
no solutions
If x < 0,
-3x = 3x+6
x = -1
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