Asked by Ryan
Derivative of (x^1/2 cscX sinX)
Answers
Answered by
mathhelper
The way you typed it ....
(x^1/2 cscX sinX)
= √x (1/sinx)(sinx)
= x^(1/2)
if y = x^(1/2)
dy/dx = (1/2)x^(-1/2) or 1/(2√x)
Not sure that's what you meant, why is the x in x^(1/2) different
than the x in cscX and sinX ?
(x^1/2 cscX sinX)
= √x (1/sinx)(sinx)
= x^(1/2)
if y = x^(1/2)
dy/dx = (1/2)x^(-1/2) or 1/(2√x)
Not sure that's what you meant, why is the x in x^(1/2) different
than the x in cscX and sinX ?
Answered by
oobleck
just use the product rule
y = √x cscx sinx
actually, since cscx sinx = 1,
y' = 1/2 x^-1/2
y = √x cscx sinx
actually, since cscx sinx = 1,
y' = 1/2 x^-1/2
Answered by
Anonymous
ah, Ryan, we seem to be doing a lot of very similar problems for you. It is time to try and post your attempts.
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