Asked by Ryan
Derivative of (x^1/2 cscX sinX)
Answers
Answered by
mathhelper
The way you typed it ....
(x^1/2 cscX sinX)
= √x (1/sinx)(sinx)
= x^(1/2)
if y = x^(1/2)
dy/dx = (1/2)x^(-1/2) or 1/(2√x)
Not sure that's what you meant, why is the x in x^(1/2) different
than the x in cscX and sinX ?
(x^1/2 cscX sinX)
= √x (1/sinx)(sinx)
= x^(1/2)
if y = x^(1/2)
dy/dx = (1/2)x^(-1/2) or 1/(2√x)
Not sure that's what you meant, why is the x in x^(1/2) different
than the x in cscX and sinX ?
Answered by
oobleck
just use the product rule
y = √x cscx sinx
actually, since cscx sinx = 1,
y' = 1/2 x^-1/2
y = √x cscx sinx
actually, since cscx sinx = 1,
y' = 1/2 x^-1/2
Answered by
Anonymous
ah, Ryan, we seem to be doing a lot of very similar problems for you. It is time to try and post your attempts.
There are no AI answers yet. The ability to request AI answers is coming soon!