prove: cscxcos*2x+sinx=cscx

express this in sinx (1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B)...

limit as x-> 0 (1+sinx)^(cscx) How do I show that this is indeterminate? Can I say that 1^(1/0)...

prove:(cscx-cotx)^4 x (cscx+cotx)^4 = 1

sinx cscx-sin^(2)x=cos^(2)x

sinx+sinxcot^2x=cscx prove each identity

Prove (1+secx)/(tanx+sinx)=cscx

cscx/1-sinx

Sinx/Cscx -1+sinx/Cscx +1= 2tan^2x

Derivative of (x^1/2 cscX sinX)

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