Asked by Allie
Find the area of the triangle with the given measurements: a=7, đŒ = 45°, đŸ = 60°.
(To the extent possible use standard angles to simplify your responses. When necessary express your answers using the functions sin, cos, sinâ1, cosâ1. If there is no solution enter IMPOSSIBLE.)
(To the extent possible use standard angles to simplify your responses. When necessary express your answers using the functions sin, cos, sinâ1, cosâ1. If there is no solution enter IMPOSSIBLE.)
Answers
Answered by
mathhelper
Using standard convention in writing the data
You have triangle ABC, with angle A = 45°, and a = 7
angle B = 60°, which would make angle C = 75°
I can find AB using the sine law:
AB/sin60 = 7/sin45
AB = 7sin60/sin45 = 7(â3/2) / (1/â2)
= (7â3/2)(â2/1) = 7â6 / 2
Now you have 2 sides and the contained angle, just like in the
previous problem I did for you.
Repeat those steps to find the area
You have triangle ABC, with angle A = 45°, and a = 7
angle B = 60°, which would make angle C = 75°
I can find AB using the sine law:
AB/sin60 = 7/sin45
AB = 7sin60/sin45 = 7(â3/2) / (1/â2)
= (7â3/2)(â2/1) = 7â6 / 2
Now you have 2 sides and the contained angle, just like in the
previous problem I did for you.
Repeat those steps to find the area