To find the area of a triangle given the lengths of its three sides (a, b, and c), we can use Heron's formula:
s = (a + b + c) / 2
Area = √[s(s - a)(s - b)(s - c)]
Given the numbers:
a = 9in, b = 7in, c = 13in
Calculate s:
s = (9 + 7 + 13) / 2
s = 29 / 2
s = 14.5
Now, calculate the area using Heron's formula:
Area = √[14.5(14.5 - 9)(14.5 - 7)(14.5 - 13)]
Area = √[14.5(5.5)(7.5)(1.5)]
Area = √2398.125
Area ≈ 48.97 square inches
Therefore, the area of the triangle with side lengths 9in, 7in, and 13in is approximately 48.97 square inches.
Find the area of the triangle. Use the formula sheet provided.
Numbers given: 9in 7in 13in 18in.
3 answers
responses are:
A. 40 in^2
B. 63 in^2
C. 126 in^2
D. 47 in^2
A. 40 in^2
B. 63 in^2
C. 126 in^2
D. 47 in^2
Using the formula for the area of a triangle when sides are given A= √[s(s-a)(s-b)(s-c)],
where s is the semi-perimeter given by (a+b+c) / 2
First, calculate the semi-perimeter (s) for the given sides: a = 9in, b = 7in, c = 13in.
s = (9 + 7 +13) / 2
s = 29 / 2
s = 14.5
Now calculate the area using the formula:
Area = √[14.5(14.5 - 9)(14.5 - 7)(14.5 - 13)]
Area = √[14.5(5.5)(7.5)(1.5)]
Area = √[729.75]
Area ≈ 27 in^2
Therefore, the correct answer from the provided options is not included in the options given. The closest option to the actual area of the triangle is not listed.
where s is the semi-perimeter given by (a+b+c) / 2
First, calculate the semi-perimeter (s) for the given sides: a = 9in, b = 7in, c = 13in.
s = (9 + 7 +13) / 2
s = 29 / 2
s = 14.5
Now calculate the area using the formula:
Area = √[14.5(14.5 - 9)(14.5 - 7)(14.5 - 13)]
Area = √[14.5(5.5)(7.5)(1.5)]
Area = √[729.75]
Area ≈ 27 in^2
Therefore, the correct answer from the provided options is not included in the options given. The closest option to the actual area of the triangle is not listed.